What is the extreme f(x,y)=2x^3-5xy^2+4y^3 ?

The extreme f(x,y)=2x^3-5xy^2+4y^3 is None

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extreme f(x,y)=2x^3-5xy^2+4y^3

extreme points

f (x, y) = 2 x^{3} - 5 x y^{2} + 4 y^{3}

None

Solution steps

Find the critical points:

None

2 x^{3} - 5 x y^{2} + 4 y^{3}

has no critical points, therefore there are no extreme points

None

f (x, y) = 2 x^{2} - x y + y^{2} - 6 x - 9 y + 7

12 x^{\frac{2}{3}} - 8 x

f (x) = 9 - x^{2}, - 3 \leq x \leq 2

f (x) = \frac{1}{x} - \frac{64}{y} + x y

f (x) = x^{2} + 8 x + 13

What is the extreme f(x,y)=2x^3-5xy^2+4y^3 ?
The extreme f(x,y)=2x^3-5xy^2+4y^3 is None