What is the extreme f(x)=-x^{2/3}(x-5) ?

The extreme f(x)=-x^{2/3}(x-5) is Minimum(0,0),Maximum(2,3*2^{2/3})

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extreme f(x)=-x^{2/3}(x-5)

extreme points

f (x) = - x^{\frac{2}{3}} (x - 5)

Minimum (0, 0), Maximum (2, 3 \cdot 2^{\frac{2}{3}})

Solution steps

f^{'} (x) = - \frac{5 x - 10}{3 x ^{\frac{1}{3}}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 0

into

- x^{\frac{2}{3}} (x - 5) : 0

Minimum (0, 0)

Plug

x = 2

into

- x^{\frac{2}{3}} (x - 5) : 3 \cdot 2^{\frac{2}{3}}

Maximum (2, 3 \cdot 2^{\frac{2}{3}})

Minimum (0, 0), Maximum (2, 3 \cdot 2^{\frac{2}{3}})

\frac{x ^{2} - 7 x + 26}{x - 5}

f (x) = 3 x^{3} e^{- x}, - 1 \leq x \leq 5

(x + 8)^{\frac{2}{3}}

f (x) = x^{2} - y^{2} - 7 x - 4 y

f (x, y) = x^{3} + y^{3} - 21 x y

What is the extreme f(x)=-x^{2/3}(x-5) ?
The extreme f(x)=-x^{2/3}(x-5) is Minimum(0,0),Maximum(2,3*2^{2/3})