What is the extreme f(x)=x^2-y^2-7x-4y ?

The extreme f(x)=x^2-y^2-7x-4y is Saddle(7/2 ,-2)

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extreme f(x)=x^2-y^2-7x-4y

extreme points

f (x) = x^{2} - y^{2} - 7 x - 4 y

Saddle (\frac{7}{2}, - 2)

Solution steps

Find the critical points:

(\frac{7}{2}, - 2)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 4

Check the sign of at each critical point

Check critical point

(\frac{7}{2}, - 2) :

Saddle

Saddle (\frac{7}{2}, - 2)

f (x, y) = x^{3} + y^{3} - 21 x y

f (x) = 2 x^{3} + 3 x^{2} - 36 x + 1

f (x) = x + e^{- 4 x}

f (x) = - 2 x^{3} + 9 x^{2} - 12 x

- \frac{5 x}{x ^{2} + 4}

What is the extreme f(x)=x^2-y^2-7x-4y ?
The extreme f(x)=x^2-y^2-7x-4y is Saddle(7/2 ,-2)