What is the extreme f(x)=-2x^3+9x^2-12x ?

The extreme f(x)=-2x^3+9x^2-12x is Minimum(1,-5),Maximum(2,-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-2x^3+9x^2-12x

extreme points

f (x) = - 2 x^{3} + 9 x^{2} - 12 x

Minimum (1, - 5), Maximum (2, - 4)

Solution steps

f^{'} (x) = - 6 x^{2} + 18 x - 12

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < 2,

Decreasing

: 2 < x < \infty

Plug

x = 1

into

- 2 x^{3} + 9 x^{2} - 12 x : - 5

Minimum (1, - 5)

Plug

x = 2

into

- 2 x^{3} + 9 x^{2} - 12 x : - 4

Maximum (2, - 4)

Minimum (1, - 5), Maximum (2, - 4)

- \frac{5 x}{x ^{2} + 4}

f (x) = x^{2} + 6 x

f (x) = x^{2} + 5 x

f (x) = x^{5} - 5 x^{3}

P (x, y) = x^{3} (x + y) + 5 x y (x + y)

What is the extreme f(x)=-2x^3+9x^2-12x ?
The extreme f(x)=-2x^3+9x^2-12x is Minimum(1,-5),Maximum(2,-4)