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Popular Functions >

extreme f(x)=x^3-3x^2+3x+2

Solution

extreme points

f (x) = x^{3} - 3 x^{2} + 3 x + 2

Solution

Saddle (1, 3)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x + 3

Find intervals:

Increasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{3} - 3 x^{2} + 3 x + 2 : 3

Saddle (1, 3)

Graph

Popular Examples

extreme f(x)=(8-4x)^8 extreme points

f (x) = (8 - 4 x)^{8}

extreme f(x)=2x^2-8x^4 extreme points

f (x) = 2 x^{2} - 8 x^{4}

extreme f(x)=-x^{2/3}(x-3),-3<= x<= 3 extreme points

f (x) = - x^{\frac{2}{3}} (x - 3), - 3 \leq x \leq 3

extreme x^{3/5}extreme points

x^{\frac{3}{5}}

extreme f(x)=(8.7x+0.2)/(x^2-4.5x+7.5)extreme points

f (x) = \frac{8.7 x + 0.2}{x ^{2} - 4.5 x + 7.5}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^3-3x^2+3x+2 ?
The extreme f(x)=x^3-3x^2+3x+2 is Saddle(1,3)