What is the extreme f(x)=5x^3-5x^2-5x+7 ?

The extreme f(x)=5x^3-5x^2-5x+7 is Maximum(-1/3 , 214/27),Minimum(1,2)

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extreme f(x)=5x^3-5x^2-5x+7

extreme points

f (x) = 5 x^{3} - 5 x^{2} - 5 x + 7

Maximum (- \frac{1}{3}, \frac{214}{27}), Minimum (1, 2)

Solution steps

f^{'} (x) = 15 x^{2} - 10 x - 5

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

5 x^{3} - 5 x^{2} - 5 x + 7 : \frac{214}{27}

Maximum (- \frac{1}{3}, \frac{214}{27})

Plug

x = 1

into

5 x^{3} - 5 x^{2} - 5 x + 7 : 2

Minimum (1, 2)

Maximum (- \frac{1}{3}, \frac{214}{27}), Minimum (1, 2)

x^{2} - 2 x + 1

f (x, y) = - x^{3} + 8 x y - 6 y^{2} + 12

f (x, y) = x^{2} + x y + y^{2} - 34 y + 385

(x - 1)^{3} + 2

f (x) = x^{5} \cdot ln (x)

What is the extreme f(x)=5x^3-5x^2-5x+7 ?
The extreme f(x)=5x^3-5x^2-5x+7 is Maximum(-1/3 , 214/27),Minimum(1,2)