What is the extreme f(x)=((42-x)x-(2x+80)) ?

The extreme f(x)=((42-x)x-(2x+80)) is Maximum(20,320)

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extreme f(x)=((42-x)x-(2x+80))

extreme points

f (x) = ((42 - x) x - (2 x + 80))

Maximum (20, 320)

Solution steps

f^{'} (x) = - 2 x + 40

Find intervals:

Increasing

: - \infty < x < 20,

Decreasing

: 20 < x < \infty

Plug

x = 20

into

(42 - x) x - (2 x + 80) : 320

Maximum (20, 320)

f (x, y) = - 4 x + y - \frac{1}{x} + \frac{1}{y}

f (x) = \frac{x ^{2} + 4}{x ^{2} - 25}

f (x) = (x - 8) ln (x - 8)

f (x) = 2 x^{2} + y^{2} - y

f (x) = x^{3} + 6 x^{2} + 12 x + 5

What is the extreme f(x)=((42-x)x-(2x+80)) ?
The extreme f(x)=((42-x)x-(2x+80)) is Maximum(20,320)