What is the extreme f(x,y)=x^3-3xy^2+y^3 ?

The extreme f(x,y)=x^3-3xy^2+y^3 is None

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=x^3-3xy^2+y^3

extreme points

f (x, y) = x^{3} - 3 x y^{2} + y^{3}

None

Solution steps

Find the critical points:

None

x^{3} - 3 x y^{2} + y^{3}

has no critical points, therefore there are no extreme points

None

f (x, y) = e^{y} (x^{2} + y^{2})

f (x) = - 2 cos (2 x)

f (x) = 3 x, - 8 \leq x \leq 8

f (x) = x^{\frac{2}{3}} - 7

f (x) = x^{4} + 2 x^{3} - 2 x + 5

What is the extreme f(x,y)=x^3-3xy^2+y^3 ?
The extreme f(x,y)=x^3-3xy^2+y^3 is None