What is the extreme f(x)=2x^3-3x^2-72x+15 ?

The extreme f(x)=2x^3-3x^2-72x+15 is Maximum(-3,150),Minimum(4,-193)

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extreme f(x)=2x^3-3x^2-72x+15

extreme points

f (x) = 2 x^{3} - 3 x^{2} - 72 x + 15

Maximum (- 3, 150), Minimum (4, - 193)

Solution steps

f^{'} (x) = 6 x^{2} - 6 x - 72

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 3

into

2 x^{3} - 3 x^{2} - 72 x + 15 : 150

Maximum (- 3, 150)

Plug

x = 4

into

2 x^{3} - 3 x^{2} - 72 x + 15 : - 193

Minimum (4, - 193)

Maximum (- 3, 150), Minimum (4, - 193)

- x^{3} - 9 x^{2}

y = \frac{x ^{2} + 2}{x ^{2} - 25}

f (x) = - sin (x) - 4, (0, 2 π)

f (x) = \frac{x + 5}{x ^{2} - 4}

f (x) = 6 + 9 x^{2} - 6 x^{3}

What is the extreme f(x)=2x^3-3x^2-72x+15 ?
The extreme f(x)=2x^3-3x^2-72x+15 is Maximum(-3,150),Minimum(4,-193)