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Popular >

extreme y=2x^2+8x+8

Solution

extreme points

y = 2 x^{2} + 8 x + 8

Solution

Minimum (- 2, 0)

Solution steps

f^{'} (x) = 4 x + 8

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

2 x^{2} + 8 x + 8 : 0

Minimum (- 2, 0)

Graph

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Frequently Asked Questions (FAQ)

What is the extreme y=2x^2+8x+8 ?
The extreme y=2x^2+8x+8 is Minimum(-2,0)