en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=2+x^{2/3}

Solution

extreme points

f (x) = 2 + x^{\frac{2}{3}}

Solution

Minimum (0, 2)

Solution steps

f^{'} (x) = \frac{2}{3 x ^{\frac{1}{3}}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

2 + x^{\frac{2}{3}} : 2

Minimum (0, 2)

Graph

Popular Examples

extreme y^2-xy-x^2 extreme points

y^{2} - x y - x^{2}

extreme f(x,y)=(2xy^2-x^2y)/(x^2+y^2)extreme points

f (x, y) = \frac{2 x y ^{2} - x ^{2} y}{x ^{2} + y ^{2}}

extreme f(x)=1+2x-3x^2 extreme points

f (x) = 1 + 2 x - 3 x^{2}

extreme f(5/4 , 1/4)=2xy-x^2-5y^2+2x+1 extreme points

f (\frac{5}{4}, \frac{1}{4}) = 2 x y - x^{2} - 5 y^{2} + 2 x + 1

extreme f(x)=3+x^2+xy+y^2 extreme points

f (x) = 3 + x^{2} + x y + y^{2}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=2+x^{2/3} ?
The extreme f(x)=2+x^{2/3} is Minimum(0,2)