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Popular >

extreme f(x)=(x-6)e^x

Solution

extreme points

f (x) = (x - 6) e^{x}

Solution

Minimum (5, - e^{5})

Solution steps

f^{'} (x) = e^{x} (x - 5)

Find intervals:

Decreasing

: - \infty < x < 5,

Increasing

: 5 < x < \infty

Plug

x = 5

into

(x - 6) e^{x} : - e^{5}

Minimum (5, - e^{5})

Graph

Popular Examples

extreme f(x)=(x+14)(x-7)^2 extreme points

f (x) = (x + 14) (x - 7)^{2}

extreme f(x)=x^3-48x,-5<= x<= 5 extreme points

f (x) = x^{3} - 48 x, - 5 \leq x \leq 5

extreme y=5x^6-3x^4+2x-9 extreme points

y = 5 x^{6} - 3 x^{4} + 2 x - 9

extreme f(x)=x^3+2xy^2-5x-4y+20 extreme points

f (x) = x^{3} + 2 x y^{2} - 5 x - 4 y + 20

extreme f(t)=5e^{at}extreme points

f (t) = 5 e^{a t}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=(x-6)e^x ?
The extreme f(x)=(x-6)e^x is Minimum(5,-e^5)