What is the extreme f(x)=(x+14)(x-7)^2 ?

The extreme f(x)=(x+14)(x-7)^2 is Maximum(-7,1372),Minimum(7,0)

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extreme f(x)=(x+14)(x-7)^2

extreme points

f (x) = (x + 14) (x - 7)^{2}

Maximum (- 7, 1372), Minimum (7, 0)

Solution steps

f^{'} (x) = 3 (x - 7) (x + 7)

Find intervals:

Increasing

: - \infty < x < - 7,

Decreasing

: - 7 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 7

into

(x + 14) (x - 7)^{2} : 1372

Maximum (- 7, 1372)

Plug

x = 7

into

(x + 14) (x - 7)^{2} : 0

Minimum (7, 0)

Maximum (- 7, 1372), Minimum (7, 0)

f (x) = x^{3} - 48 x, - 5 \leq x \leq 5

y = 5 x^{6} - 3 x^{4} + 2 x - 9

f (x) = x^{3} + 2 x y^{2} - 5 x - 4 y + 20

f (t) = 5 e^{a t}

f (x) = I x - 4 I

What is the extreme f(x)=(x+14)(x-7)^2 ?
The extreme f(x)=(x+14)(x-7)^2 is Maximum(-7,1372),Minimum(7,0)