What is the extreme f(x)=Ix-4I ?

The extreme f(x)=Ix-4I is Saddle(4,0)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=Ix-4I

extreme points

f (x) = I x - 4 I

Saddle (4, 0)

Solution steps

Find the critical points:

(4, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, I) = - 1

Check the sign of at each critical point

Check critical point

(4, 0) :

Saddle

Saddle (4, 0)

f (x) = x ((\frac{1}{3}) x - 2)^{3} + 10

f (x) = \frac{x}{x ^{2} - x + 25}, 0 \leq x \leq 27

A - \frac{2}{X - 2} + \frac{1}{( X - 2 ) ^{2}}

f (x, y) = 2 x^{2} + 3 y^{2} - 4 x + 12 y + 13

f (x) = x^{3} - x^{2} - x + 7