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Popular >

extreme y=x^2-2x+1

Solution

extreme points

y = x^{2} - 2 x + 1

Solution

Minimum (1, 0)

Solution steps

f^{'} (x) = 2 x - 2

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

x^{2} - 2 x + 1 : 0

Minimum (1, 0)

Graph

Popular Examples

extreme f(x)=(x^2-35)/(x-6)extreme points

f (x) = \frac{x ^{2} - 35}{x - 6}

extreme x^3-18x^2+81x extreme points

x^{3} - 18 x^{2} + 81 x

extreme f(x,y)=x^2+xy+y^2+8y extreme points

f (x, y) = x^{2} + x y + y^{2} + 8 y

extreme f(x,y)=x^2+xy+y^2+5y extreme points

f (x, y) = x^{2} + x y + y^{2} + 5 y

extreme (x^2-9)/(x^2-4)extreme points

\frac{x ^{2} - 9}{x ^{2} - 4}

Frequently Asked Questions (FAQ)

What is the extreme y=x^2-2x+1 ?
The extreme y=x^2-2x+1 is Minimum(1,0)