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Popular >

extreme (x^2-9)/(x^2-4)

Solution

extreme points

\frac{x ^{2} - 9}{x ^{2} - 4}

Solution

Minimum (0, \frac{9}{4})

Solution steps

f^{'} (x) = \frac{10 x}{( x ^{2} - 4 ) ^{2}}

Find intervals:

Decreasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = 0

into

\frac{x ^{2} - 9}{x ^{2} - 4} : \frac{9}{4}

Minimum (0, \frac{9}{4})

Graph

Popular Examples

extreme y=2x^3-6x+1 extreme points

y = 2 x^{3} - 6 x + 1

extreme f(x)=-9+x^2 extreme points

f (x) = - 9 + x^{2}

extreme f(x)=(-1)/(x-6)extreme points

f (x) = \frac{- 1}{x - 6}

extreme f(x,y)=x^3-18xy+y^3 extreme points

f (x, y) = x^{3} - 18 x y + y^{3}

extreme f(x)=x^4-3x^3+x^2 extreme points

f (x) = x^{4} - 3 x^{3} + x^{2}

Frequently Asked Questions (FAQ)

What is the extreme (x^2-9)/(x^2-4) ?
The extreme (x^2-9)/(x^2-4) is Minimum(0, 9/4)