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Popular >

extreme f(x)=x^2+x-12

Solution

extreme points

f (x) = x^{2} + x - 12

Solution

Minimum (- \frac{1}{2}, - \frac{49}{4})

Solution steps

f^{'} (x) = 2 x + 1

Find intervals:

Decreasing

: - \infty < x < - \frac{1}{2},

Increasing

: - \frac{1}{2} < x < \infty

Plug

x = - \frac{1}{2}

into

x^{2} + x - 12 : - \frac{49}{4}

Minimum (- \frac{1}{2}, - \frac{49}{4})

Graph

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+x-12 ?
The extreme f(x)=x^2+x-12 is Minimum(-1/2 ,-49/4)