What is the extreme f(x)=-x^3+3x^2+9x-1 ?

The extreme f(x)=-x^3+3x^2+9x-1 is Minimum(-1,-6),Maximum(3,26)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=-x^3+3x^2+9x-1

extreme points

f (x) = - x^{3} + 3 x^{2} + 9 x - 1

Minimum (- 1, - 6), Maximum (3, 26)

Solution steps

f^{'} (x) = - 3 x^{2} + 6 x + 9

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 3,

Decreasing

: 3 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x^{2} + 9 x - 1 : - 6

Minimum (- 1, - 6)

Plug

x = 3

into

- x^{3} + 3 x^{2} + 9 x - 1 : 26

Maximum (3, 26)

Minimum (- 1, - 6), Maximum (3, 26)

f (t) = 120 - 120 h (t - 2)

f (x) = x^{6} (1 - x)^{18}

f (x) = x^{3} - x^{2} - x + 4, - 1 \leq x \leq 2

f (x, y) = - (x^{2} - y^{2}) e^{- x^{2} - y^{2}}

f (x) = x^{2} lo g_{2} (x)

What is the extreme f(x)=-x^3+3x^2+9x-1 ?
The extreme f(x)=-x^3+3x^2+9x-1 is Minimum(-1,-6),Maximum(3,26)