What is the extreme f(x)=x^2-4x,-infinity <x<= 4 ?

The extreme f(x)=x^2-4x,-infinity <x<= 4 is Minimum(2,-4),Maximum(4,0)

Popular >

extreme f(x)=x^2-4x,-infinity <x<= 4

extreme points

f (x) = x^{2} - 4 x, - \infty < x \leq 4

Minimum (2, - 4), Maximum (4, 0)

Solution steps

Find the critical points:

x = 2, x = 4

Domain of

x^{2} - 4 x, - \infty < x \leq 4 : x \leq 4

Find intervals:

Decreasing

: - \infty < x < 2,

Increasing

: 2 < x < 4

Plug the extreme point

x = 2

into

x^{2} - 4 x \Rightarrow y = - 4

Minimum (2, - 4)

Plug the extreme point

x = 4

into

x^{2} - 4 x \Rightarrow y = 0

Maximum (4, 0)

Minimum (2, - 4), Maximum (4, 0)

f (x) = (x - 2) (x + 2) (x + 4)

f (x) = \frac{x + 1}{x ^{2} - 6 x - 7}

f (x) = 11 + 5 x + x^{2}

f (x) = x^{2} lo g_{3} (x)

f (x) = \frac{x ^{2} - 9 x + 50}{x - 7}

What is the extreme f(x)=x^2-4x,-infinity <x<= 4 ?
The extreme f(x)=x^2-4x,-infinity <x<= 4 is Minimum(2,-4),Maximum(4,0)