What is the extreme f(x)=x^2log_{3}(x) ?

The extreme f(x)=x^2log_{3}(x) is Minimum(1/(sqrt(e)),-1/(2e)log_{3}(e))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^2log_{3}(x)

extreme points

f (x) = x^{2} lo g_{3} (x)

Minimum (\frac{1}{e}, - \frac{1}{2 e} lo g_{3} (e))

Solution steps

f^{'} (x) = \frac{x + 2 x ln ( x )}{ln ( 3 )}

Find intervals:

Decreasing

: 0 < x < \frac{1}{e},

Increasing

: \frac{1}{e} < x < \infty

Plug

x = \frac{1}{e}

into

x^{2} lo g_{3} (x) : - \frac{1}{2 e} lo g_{3} (e)

Minimum (\frac{1}{e}, - \frac{1}{2 e} lo g_{3} (e))

f (x) = \frac{x ^{2} - 9 x + 50}{x - 7}

- \frac{4}{x - 7}

f (x, y) = - 4 x^{2} - 2 y^{2} - 8 x + 12 y + 5

f (x, y) = \frac{4}{x + y}

f (x) = - x^{2} + 9, - 3 \leq x \leq 4

What is the extreme f(x)=x^2log_{3}(x) ?
The extreme f(x)=x^2log_{3}(x) is Minimum(1/(sqrt(e)),-1/(2e)log_{3}(e))