What is the extreme f(x)=(11-x)(x+1)^2 ?

The extreme f(x)=(11-x)(x+1)^2 is Minimum(-1,0),Maximum(7,256)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=(11-x)(x+1)^2

extreme points

f (x) = (11 - x) (x + 1)^{2}

Minimum (- 1, 0), Maximum (7, 256)

Solution steps

f^{'} (x) = - 3 (x + 1) (x - 7)

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 7,

Decreasing

: 7 < x < \infty

Plug

x = - 1

into

(11 - x) (x + 1)^{2} : 0

Minimum (- 1, 0)

Plug

x = 7

into

(11 - x) (x + 1)^{2} : 256

Maximum (7, 256)

Minimum (- 1, 0), Maximum (7, 256)

f (x, y) = 400 - 16 x^{2} - 49 y^{2}

f (x) = 4 x^{3} + 9 x^{2} - 12 x + 5

f (x) = x^{3} - 27 x + 5

f (x) = 6 x + \frac{384}{x}

f (x) = - 2 x^{3} + 36 x^{2} - 192 x

What is the extreme f(x)=(11-x)(x+1)^2 ?
The extreme f(x)=(11-x)(x+1)^2 is Minimum(-1,0),Maximum(7,256)