What is the extreme y(x,t)=x(3t) ?

The extreme y(x,t)=x(3t) is Saddle(0,0)

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extreme y(x,t)=x(3t)

extreme points

y (x, t) = x (3 t)

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = 0

D (x, t) = - 9

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

f (x) = 3 x^{\frac{2}{3}} - 2 x [- 1.1]

f (x) = x^{2} + 3 x + 5

f (x, y) = \frac{1}{3} 36 - 4 x^{2} - 9 y^{2}

f (x) = 0.2 (x^{4} + 4 x^{3} - 16 x - 16) + 5

f (x) = \frac{3 x}{x ^{2} + 2 x - 8}