What is the extreme f(x)=2x^3+9x^2+12x-9 ?

The extreme f(x)=2x^3+9x^2+12x-9 is Maximum(-2,-13),Minimum(-1,-14)

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extreme f(x)=2x^3+9x^2+12x-9

extreme points

f (x) = 2 x^{3} + 9 x^{2} + 12 x - 9

Maximum (- 2, - 13), Minimum (- 1, - 14)

Solution steps

f^{'} (x) = 6 x^{2} + 18 x + 12

Find intervals:

Increasing

: - \infty < x < - 2,

Decreasing

: - 2 < x < - 1,

Increasing

: - 1 < x < \infty

Plug

x = - 2

into

2 x^{3} + 9 x^{2} + 12 x - 9 : - 13

Maximum (- 2, - 13)

Plug

x = - 1

into

2 x^{3} + 9 x^{2} + 12 x - 9 : - 14

Minimum (- 1, - 14)

Maximum (- 2, - 13), Minimum (- 1, - 14)

f (x, y) = 7 x^{2} - x y + 10 y^{2}

f (x) = x^{3} - 3 x^{2} - 105 x

\frac{1}{x - 3}

f (x) = x \cdot y

f (x, y) = 2 x^{3} + x^{2} y^{2} - 6 x - 4 y^{2} + 5

What is the extreme f(x)=2x^3+9x^2+12x-9 ?
The extreme f(x)=2x^3+9x^2+12x-9 is Maximum(-2,-13),Minimum(-1,-14)