What is the extreme f(x)=x^3-3x^2-105x ?

The extreme f(x)=x^3-3x^2-105x is Maximum(-5,325),Minimum(7,-539)

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extreme f(x)=x^3-3x^2-105x

extreme points

f (x) = x^{3} - 3 x^{2} - 105 x

Maximum (- 5, 325), Minimum (7, - 539)

Solution steps

f^{'} (x) = 3 x^{2} - 6 x - 105

Find intervals:

Increasing

: - \infty < x < - 5,

Decreasing

: - 5 < x < 7,

Increasing

: 7 < x < \infty

Plug

x = - 5

into

x^{3} - 3 x^{2} - 105 x : 325

Maximum (- 5, 325)

Plug

x = 7

into

x^{3} - 3 x^{2} - 105 x : - 539

Minimum (7, - 539)

Maximum (- 5, 325), Minimum (7, - 539)

\frac{1}{x - 3}

f (x) = x \cdot y

f (x, y) = 2 x^{3} + x^{2} y^{2} - 6 x - 4 y^{2} + 5

f (x, y) = y e^{x^{2} - y^{2}}

f (x, y) = \frac{1}{3} x^{3} + \frac{4}{3} y^{3} - x^{2} - 3 x - 4 y - 3

What is the extreme f(x)=x^3-3x^2-105x ?
The extreme f(x)=x^3-3x^2-105x is Maximum(-5,325),Minimum(7,-539)