What is the extreme f(x)=3x^4-8^3-6x^2+24x-2 ?

The extreme f(x)=3x^4-8^3-6x^2+24x-2 is Minimum(-1.52137…,-548.32862…)

Popular >

extreme f(x)=3x^4-8^3-6x^2+24x-2

extreme points

f (x) = 3 x^{4} - 8^{3} - 6 x^{2} + 24 x - 2

Minimum (- 1.52137 \dots, - 548.32862 \dots)

Solution steps

Find the critical points:

x \approx - 1.52137 \dots

Domain of

3 x^{4} - 8^{3} - 6 x^{2} + 24 x - 2 : - \infty < x < \infty

Find intervals:

Decreasing

: - \infty < x < - 1.52137 \dots,

Increasing

: - 1.52137 \dots < x < \infty

Plug the extreme point

x = - 1.52137 \dots

into

3 x^{4} - 8^{3} - 6 x^{2} + 24 x - 2 \Rightarrow y = - 548.32862 \dots

Minimum (- 1.52137 \dots, - 548.32862 \dots)

f (x) = x^{3} - 5 x^{2} - 8 x - 8

f (x) = 9 x + 9 sin (x), 0 \leq x \leq 2 π

f (x) = x e^{- 4 x^{2}}

y = x^{\frac{2}{5}} (x + 3)

f (x) = x^{2} + x + 3

What is the extreme f(x)=3x^4-8^3-6x^2+24x-2 ?
The extreme f(x)=3x^4-8^3-6x^2+24x-2 is Minimum(-1.52137…,-548.32862…)