What is the extreme f(x)=x^3+2x^2-20x ?

The extreme f(x)=x^3+2x^2-20x is Maximum(-10/3 , 1400/27),Minimum(2,-24)

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extreme f(x)=x^3+2x^2-20x

extreme points

f (x) = x^{3} + 2 x^{2} - 20 x

Maximum (- \frac{10}{3}, \frac{1400}{27}), Minimum (2, - 24)

Solution steps

f^{'} (x) = 3 x^{2} + 4 x - 20

Find intervals:

Increasing

: - \infty < x < - \frac{10}{3},

Decreasing

: - \frac{10}{3} < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - \frac{10}{3}

into

x^{3} + 2 x^{2} - 20 x : \frac{1400}{27}

Maximum (- \frac{10}{3}, \frac{1400}{27})

Plug

x = 2

into

x^{3} + 2 x^{2} - 20 x : - 24

Minimum (2, - 24)

Maximum (- \frac{10}{3}, \frac{1400}{27}), Minimum (2, - 24)

e^{4 x} + e^{- x}

f (x) = x^{2} - 12 x + 8

f (x) = \frac{2 x ^{2}}{x ^{2} - 1}

f (x, y) = x^{2} + 5 x y + y^{2}

12 x e^{- x}

What is the extreme f(x)=x^3+2x^2-20x ?
The extreme f(x)=x^3+2x^2-20x is Maximum(-10/3 , 1400/27),Minimum(2,-24)