What is the extreme f(x)=-x^3+3x-10 ?

The extreme f(x)=-x^3+3x-10 is Minimum(-1,-12),Maximum(1,-8)

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extreme f(x)=-x^3+3x-10

extreme points

f (x) = - x^{3} + 3 x - 10

Minimum (- 1, - 12), Maximum (1, - 8)

Solution steps

f^{'} (x) = - 3 x^{2} + 3

Find intervals:

Decreasing

: - \infty < x < - 1,

Increasing

: - 1 < x < 1,

Decreasing

: 1 < x < \infty

Plug

x = - 1

into

- x^{3} + 3 x - 10 : - 12

Minimum (- 1, - 12)

Plug

x = 1

into

- x^{3} + 3 x - 10 : - 8

Maximum (1, - 8)

Minimum (- 1, - 12), Maximum (1, - 8)

uv

y = 4 x + 4 sin (x)

f (x, y) = x^{3} + y^{3} - 147 x - 75 y - 10

f (x) = x^{3} - 4 x^{2} - 16 x + 2

f (x) = x^{3} - 4 x^{2} - 16 x - 1

What is the extreme f(x)=-x^3+3x-10 ?
The extreme f(x)=-x^3+3x-10 is Minimum(-1,-12),Maximum(1,-8)