What is the extreme f(x,y)=x^2-6xy+y^2+16y+9 ?

The extreme f(x,y)=x^2-6xy+y^2+16y+9 is Saddle(3,1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x,y)=x^2-6xy+y^2+16y+9

extreme points

f (x, y) = x^{2} - 6 x y + y^{2} + 16 y + 9

Saddle (3, 1)

Solution steps

Find the critical points:

(3, 1)

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = - 32

Check the sign of at each critical point

Check critical point

(3, 1) :

Saddle

Saddle (3, 1)

f (x y) = x y + 4 x

f (x) = \frac{3 x ^{5} - 20 x ^{3}}{32}

f (x) = x + 2

f (x) = x^{2} - 10, - 3 \leq x \leq 4

f (x) = 4 - x^{2}, - 7 \leq x \leq 7

What is the extreme f(x,y)=x^2-6xy+y^2+16y+9 ?
The extreme f(x,y)=x^2-6xy+y^2+16y+9 is Saddle(3,1)