What is the extreme f(x)=xsqrt(600-x) ?

The extreme f(x)=xsqrt(600-x) is Maximum(400,4000sqrt(2)),Minimum(600,0)

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extreme f(x)=xsqrt(600-x)

extreme points

f (x) = x 600 - x

Maximum (400, 40002), Minimum (600, 0)

Solution steps

f^{'} (x) = - \frac{3 ( x - 400 )}{2 600 - x}

Find intervals:

Increasing

: - \infty < x < 400,

Decreasing

: 400 < x < 600

Plug

x = 400

into

x 600 - x : 40002

Maximum (400, 40002)

Plug

x = 600

into

x 600 - x : 0

Minimum (600, 0)

Maximum (400, 40002), Minimum (600, 0)

f (x, y) = x (y + 1) + (x + y + 1)

f (x) = \frac{( x ^{2} - 5 )}{x + 3}

f (x) = \frac{25}{2} x^{2} - ln (x)

f (x) = - 2 x^{3} + 33 x^{2} - 144 x + 1

y = - 2 x^{2} - 3 x + 1

What is the extreme f(x)=xsqrt(600-x) ?
The extreme f(x)=xsqrt(600-x) is Maximum(400,4000sqrt(2)),Minimum(600,0)