What is the extreme f(x,y)=x^3+y^2-6xy+9x+5y+2 ?

The extreme f(x,y)=x^3+y^2-6xy+9x+5y+2 is Minimum(4, 19/2),Saddle(2, 7/2)

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extreme f(x,y)=x^3+y^2-6xy+9x+5y+2

extreme points

f (x, y) = x^{3} + y^{2} - 6 x y + 9 x + 5 y + 2

Minimum (4, \frac{19}{2}), Saddle (2, \frac{7}{2})

Solution steps

Find the critical points:

(4, \frac{19}{2}), (2, \frac{7}{2})

\frac{\partial ^{2} f}{\partial x ^{2}} = 2

D (x, y) = 12 x - 36

Check the sign of at each critical point

Check critical point

(4, \frac{19}{2}) :

Minimum

Check critical point

(2, \frac{7}{2}) :

Saddle

Minimum (4, \frac{19}{2}), Saddle (2, \frac{7}{2})

f (x, y) = 100 \cdot (y - x^{2})^{2} + (x - 1)^{2}

f (x) = x^{4} - 8 x^{3} + 9

f (x) = x^{2} + 25

y = x^{x}, x > 0

f (x) = x^{3} - 4 x^{2} - 3 x + 7

What is the extreme f(x,y)=x^3+y^2-6xy+9x+5y+2 ?
The extreme f(x,y)=x^3+y^2-6xy+9x+5y+2 is Minimum(4, 19/2),Saddle(2, 7/2)