en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=4x^2-8x

Solution

extreme points

f (x) = 4 x^{2} - 8 x

Solution

Minimum (1, - 4)

Solution steps

f^{'} (x) = 8 x - 8

Find intervals:

Decreasing

: - \infty < x < 1,

Increasing

: 1 < x < \infty

Plug

x = 1

into

4 x^{2} - 8 x : - 4

Minimum (1, - 4)

Popular Examples

extreme f(x,y)=xy^2-x^2y-3xy extreme points

f (x, y) = x y^{2} - x^{2} y - 3 x y

extreme f(x)=x^4-6x^2,0<= x<= 3 extreme points

f (x) = x^{4} - 6 x^{2}, 0 \leq x \leq 3

extreme f(x,y)=(x+4y)e^{x-y^2}extreme points

f (x, y) = (x + 4 y) e^{x - y^{2}}

solvefor V,V=31pir2h solve for

V, V = 31 π r 2 h

extreme f(x)=x^3-3x^2-45x+9 extreme points

f (x) = x^{3} - 3 x^{2} - 45 x + 9

Frequently Asked Questions (FAQ)

What is the extreme f(x)=4x^2-8x ?
The extreme f(x)=4x^2-8x is Minimum(1,-4)