What is the extreme f(x)=x(x^2-3) ?

The extreme f(x)=x(x^2-3) is Maximum(-1,2),Minimum(1,-2)

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extreme f(x)=x(x^2-3)

extreme points

f (x) = x (x^{2} - 3)

Maximum (- 1, 2), Minimum (1, - 2)

Solution steps

f^{'} (x) = 3 (x + 1) (x - 1)

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x (x^{2} - 3) : 2

Maximum (- 1, 2)

Plug

x = 1

into

x (x^{2} - 3) : - 2

Minimum (1, - 2)

Maximum (- 1, 2), Minimum (1, - 2)

f (x, y) = 3 x^{2} + 10 x y + 7 y^{2} + 3 x y^{2} + 8 x^{2} y

f (x, y) = y e^{- x}

f (x) = - 3 x^{2} - x + 2

f (x) = x^{2} + 2 x + 1

f (x, y) = (x - 1) (y + 2) (x + y - 2)

What is the extreme f(x)=x(x^2-3) ?
The extreme f(x)=x(x^2-3) is Maximum(-1,2),Minimum(1,-2)