What is the extreme f(x)=2x^2ln(x)-21x^2 ?

The extreme f(x)=2x^2ln(x)-21x^2 is Minimum(e^{10},-e^{20})

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extreme f(x)=2x^2ln(x)-21x^2

extreme points

f (x) = 2 x^{2} ln (x) - 21 x^{2}

Minimum (e^{10}, - e^{20})

Solution steps

f^{'} (x) = 4 x (ln (x) - 10)

Find intervals:

Decreasing

: 0 < x < e^{10},

Increasing

: e^{10} < x < \infty

Plug

x = e^{10}

into

2 x^{2} ln (x) - 21 x^{2} : - e^{20}

Minimum (e^{10}, - e^{20})

\frac{x + 1}{x ^{2} - 8 x - 9}

y = e^{- 4 t} - e^{- 5 t}

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 20

f (x) = 3 x^{2} + y^{2} - 6 x - 4 y + 7

f (x) = 9 x^{10} - 3 x^{9}

What is the extreme f(x)=2x^2ln(x)-21x^2 ?
The extreme f(x)=2x^2ln(x)-21x^2 is Minimum(e^{10},-e^{20})