What is the extreme f(x)=2x^3-9x^2-24x+20 ?

The extreme f(x)=2x^3-9x^2-24x+20 is Maximum(-1,33),Minimum(4,-92)

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extreme f(x)=2x^3-9x^2-24x+20

extreme points

f (x) = 2 x^{3} - 9 x^{2} - 24 x + 20

Maximum (- 1, 33), Minimum (4, - 92)

Solution steps

f^{'} (x) = 6 x^{2} - 18 x - 24

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 4,

Increasing

: 4 < x < \infty

Plug

x = - 1

into

2 x^{3} - 9 x^{2} - 24 x + 20 : 33

Maximum (- 1, 33)

Plug

x = 4

into

2 x^{3} - 9 x^{2} - 24 x + 20 : - 92

Minimum (4, - 92)

Maximum (- 1, 33), Minimum (4, - 92)

f (x) = 3 x^{2} + y^{2} - 6 x - 4 y + 7

f (x) = 9 x^{10} - 3 x^{9}

28 x^{2} + 47 x + 15

- 2 x^{2} - 8 x + 2

\frac{x ^{5}}{20} - 4 x^{3}

What is the extreme f(x)=2x^3-9x^2-24x+20 ?
The extreme f(x)=2x^3-9x^2-24x+20 is Maximum(-1,33),Minimum(4,-92)