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Popular >

extreme 28x^2+47x+15

Solution

extreme points

28 x^{2} + 47 x + 15

Solution

Minimum (- \frac{47}{56}, - \frac{529}{112})

Solution steps

f^{'} (x) = 56 x + 47

Find intervals:

Decreasing

: - \infty < x < - \frac{47}{56},

Increasing

: - \frac{47}{56} < x < \infty

Plug

x = - \frac{47}{56}

into

28 x^{2} + 47 x + 15 : - \frac{529}{112}

Minimum (- \frac{47}{56}, - \frac{529}{112})

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Frequently Asked Questions (FAQ)

What is the extreme 28x^2+47x+15 ?
The extreme 28x^2+47x+15 is Minimum(-47/56 ,-529/112)