What is the extreme f(x)=6x^2-12,-4<= x<= 1 ?

The extreme f(x)=6x^2-12,-4<= x<= 1 is Maximum(-4,84),Minimum(0,-12),Maximum(1,-6)

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extreme f(x)=6x^2-12,-4<= x<= 1

extreme points

f (x) = 6 x^{2} - 12, - 4 \leq x \leq 1

Maximum (- 4, 84), Minimum (0, - 12), Maximum (1, - 6)

Solution steps

Find the critical points:

x = - 4, x = 0, x = 1

Domain of

6 x^{2} - 12, - 4 \leq x \leq 1 : - 4 \leq x \leq 1

Find intervals:

Decreasing

: - 4 < x < 0,

Increasing

: 0 < x < 1

Plug the extreme point

x = - 4

into

6 x^{2} - 12 \Rightarrow y = 84

Maximum (- 4, 84)

Plug the extreme point

x = 0

into

6 x^{2} - 12 \Rightarrow y = - 12

Minimum (0, - 12)

Plug the extreme point

x = 1

into

6 x^{2} - 12 \Rightarrow y = - 6

Maximum (1, - 6)

Maximum (- 4, 84), Minimum (0, - 12), Maximum (1, - 6)

f (y, x) = 0.6 x + 0.1 y - 0.01 x y

f (x) = 3 x^{4} - 8 x^{3} + 10

f (x) = x^{2} - 7 x + 12

f (x) = (x - 2)^{\frac{1}{3}}

f (x) = - x^{3} + x^{2} - 9 x + 8, - 1 \leq x \leq 5

What is the extreme f(x)=6x^2-12,-4<= x<= 1 ?
The extreme f(x)=6x^2-12,-4<= x<= 1 is Maximum(-4,84),Minimum(0,-12),Maximum(1,-6)