What is the extreme f(x)=x^2-1,-2<= x<= 1 ?

The extreme f(x)=x^2-1,-2<= x<= 1 is Maximum(-2,3),Minimum(0,-1),Maximum(1,0)

Popular >

extreme f(x)=x^2-1,-2<= x<= 1

extreme points

f (x) = x^{2} - 1, - 2 \leq x \leq 1

Maximum (- 2, 3), Minimum (0, - 1), Maximum (1, 0)

Solution steps

Find the critical points:

x = - 2, x = 0, x = 1

Domain of

x^{2} - 1, - 2 \leq x \leq 1 : - 2 \leq x \leq 1

Find intervals:

Decreasing

: - 2 < x < 0,

Increasing

: 0 < x < 1

Plug the extreme point

x = - 2

into

x^{2} - 1 \Rightarrow y = 3

Maximum (- 2, 3)

Plug the extreme point

x = 0

into

x^{2} - 1 \Rightarrow y = - 1

Minimum (0, - 1)

Plug the extreme point

x = 1

into

x^{2} - 1 \Rightarrow y = 0

Maximum (1, 0)

Maximum (- 2, 3), Minimum (0, - 1), Maximum (1, 0)

f (x) = - x^{3} + x^{2} + 8 x + 9

f (x) = x^{2} + 5 x - 3

f (x) = x^{2} + 5 x - 4

f (x, y) = x y e^{(x + 2 y)}

f (x) = x^{3} + y^{3} - 3 x - 3 y

What is the extreme f(x)=x^2-1,-2<= x<= 1 ?
The extreme f(x)=x^2-1,-2<= x<= 1 is Maximum(-2,3),Minimum(0,-1),Maximum(1,0)