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Popular >

extreme f(x)=x^2+5x-4

Solution

extreme points

f (x) = x^{2} + 5 x - 4

Solution

Minimum (- \frac{5}{2}, - \frac{41}{4})

Solution steps

f^{'} (x) = 2 x + 5

Find intervals:

Decreasing

: - \infty < x < - \frac{5}{2},

Increasing

: - \frac{5}{2} < x < \infty

Plug

x = - \frac{5}{2}

into

x^{2} + 5 x - 4 : - \frac{41}{4}

Minimum (- \frac{5}{2}, - \frac{41}{4})

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Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^2+5x-4 ?
The extreme f(x)=x^2+5x-4 is Minimum(-5/2 ,-41/4)