What is the extreme f(x)=x^3-27x+50 ?

The extreme f(x)=x^3-27x+50 is Maximum(-3,104),Minimum(3,-4)

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extreme f(x)=x^3-27x+50

extreme points

f (x) = x^{3} - 27 x + 50

Maximum (- 3, 104), Minimum (3, - 4)

Solution steps

f^{'} (x) = 3 x^{2} - 27

Find intervals:

Increasing

: - \infty < x < - 3,

Decreasing

: - 3 < x < 3,

Increasing

: 3 < x < \infty

Plug

x = - 3

into

x^{3} - 27 x + 50 : 104

Maximum (- 3, 104)

Plug

x = 3

into

x^{3} - 27 x + 50 : - 4

Minimum (3, - 4)

Maximum (- 3, 104), Minimum (3, - 4)

g (x) = x^{3} - 3 x + 2

f (x) = x^{3} - 3 x + 11

f (x, y) = 144 - 9 x^{2} - 16 y^{2}

f (x) = 24 x^{3} - 3 x^{4}

3 x^{2} - 12 x y + y^{3} + 3 y^{2}

What is the extreme f(x)=x^3-27x+50 ?
The extreme f(x)=x^3-27x+50 is Maximum(-3,104),Minimum(3,-4)