What is the extreme f(x)=x^3-3x+11 ?

The extreme f(x)=x^3-3x+11 is Maximum(-1,13),Minimum(1,9)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=x^3-3x+11

extreme points

f (x) = x^{3} - 3 x + 11

Maximum (- 1, 13), Minimum (1, 9)

Solution steps

f^{'} (x) = 3 x^{2} - 3

Find intervals:

Increasing

: - \infty < x < - 1,

Decreasing

: - 1 < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - 1

into

x^{3} - 3 x + 11 : 13

Maximum (- 1, 13)

Plug

x = 1

into

x^{3} - 3 x + 11 : 9

Minimum (1, 9)

Maximum (- 1, 13), Minimum (1, 9)

f (x, y) = 144 - 9 x^{2} - 16 y^{2}

f (x) = 24 x^{3} - 3 x^{4}

3 x^{2} - 12 x y + y^{3} + 3 y^{2}

f (x, y) = 4 x^{3} - y^{3} + 2 x^{2} + 3 y^{2}

1 + \frac{7}{x} - \frac{3}{x ^{2}}

What is the extreme f(x)=x^3-3x+11 ?
The extreme f(x)=x^3-3x+11 is Maximum(-1,13),Minimum(1,9)