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Popular >

extreme 1+7/x-3/(x^2)

Solution

extreme points

1 + \frac{7}{x} - \frac{3}{x ^{2}}

Solution

Maximum (\frac{6}{7}, \frac{61}{12})

Solution steps

f^{'} (x) = \frac{6}{x ^{3}} - \frac{7}{x ^{2}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \frac{6}{7},

Decreasing

: \frac{6}{7} < x < \infty

Plug

x = \frac{6}{7}

into

1 + \frac{7}{x} - \frac{3}{x ^{2}} : \frac{61}{12}

Maximum (\frac{6}{7}, \frac{61}{12})

Popular Examples

extreme f(x)= x/(x^2+1),-2<= x<= 2 extreme points

f (x) = \frac{x}{x ^{2} + 1}, - 2 \leq x \leq 2

extreme f(x)=-3+x-x^2 extreme points

f (x) = - 3 + x - x^{2}

extreme f(x)=5+54x+2x^3,0<= x<= 4 extreme points

f (x) = 5 + 54 x + 2 x^{3}, 0 \leq x \leq 4

extreme f(x)=x^3-4x^2+5x extreme points

f (x) = x^{3} - 4 x^{2} + 5 x

extreme f(x)=(x^3)/3-4x^2+12x,0<= x<= 7 extreme points

f (x) = \frac{x ^{3}}{3} - 4 x^{2} + 12 x, 0 \leq x \leq 7

Frequently Asked Questions (FAQ)

What is the extreme 1+7/x-3/(x^2) ?
The extreme 1+7/x-3/(x^2) is Maximum(6/7 , 61/12)