en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

extreme f(x)=3x^2+2

Solution

extreme points

f (x) = 3 x^{2} + 2

Solution

Minimum (0, 2)

Solution steps

f^{'} (x) = 6 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

3 x^{2} + 2 : 2

Minimum (0, 2)

Popular Examples

extreme x^2+x-6 extreme points

x^{2} + x - 6

extreme f(x)= 7/4 x^2-21/2 x+51/4 extreme points

f (x) = \frac{7}{4} x^{2} - \frac{21}{2} x + \frac{51}{4}

derivative of 7x^3y^2+34x^2y^5

\frac{d}{d x} (7 x^{3} y^{2} + 34 x^{2} y^{5})

extreme f(x)=7x^9-9x^7-7,-3<= x<= 3 extreme points

f (x) = 7 x^{9} - 9 x^{7} - 7, - 3 \leq x \leq 3

extreme f(x)=(e^x)/(3+e^x)extreme points

f (x) = \frac{e ^{x}}{3 + e ^{x}}

Frequently Asked Questions (FAQ)

What is the extreme f(x)=3x^2+2 ?
The extreme f(x)=3x^2+2 is Minimum(0,2)