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Popular >

extreme 4x^2+16x+9

Solution

extreme points

4 x^{2} + 16 x + 9

Solution

Minimum (- 2, - 7)

Solution steps

f^{'} (x) = 8 x + 16

Find intervals:

Decreasing

: - \infty < x < - 2,

Increasing

: - 2 < x < \infty

Plug

x = - 2

into

4 x^{2} + 16 x + 9 : - 7

Minimum (- 2, - 7)

Graph

Popular Examples

extreme f(x,y)=(x^2+4y^2)e^{1-x^2-y^2}extreme points

f (x, y) = (x^{2} + 4 y^{2}) e^{1 - x^{2} - y^{2}}

extreme f(x)=(-3)/(x-5)extreme points

f (x) = \frac{- 3}{x - 5}

extreme f(x)=(-4)/(x-5)extreme points

f (x) = \frac{- 4}{x - 5}

extreme f(x)=2x^3-3x^2-12x-18 extreme points

f (x) = 2 x^{3} - 3 x^{2} - 12 x - 18

extreme f(x,y)=18xy-x^3-9y^2 extreme points

f (x, y) = 18 x y - x^{3} - 9 y^{2}

Frequently Asked Questions (FAQ)

What is the extreme 4x^2+16x+9 ?
The extreme 4x^2+16x+9 is Minimum(-2,-7)