What is the extreme f(x)=x^3-x^2-x+10 ?

The extreme f(x)=x^3-x^2-x+10 is Maximum(-1/3 , 275/27),Minimum(1,9)

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extreme f(x)=x^3-x^2-x+10

extreme points

f (x) = x^{3} - x^{2} - x + 10

Maximum (- \frac{1}{3}, \frac{275}{27}), Minimum (1, 9)

Solution steps

f^{'} (x) = 3 x^{2} - 2 x - 1

Find intervals:

Increasing

: - \infty < x < - \frac{1}{3},

Decreasing

: - \frac{1}{3} < x < 1,

Increasing

: 1 < x < \infty

Plug

x = - \frac{1}{3}

into

x^{3} - x^{2} - x + 10 : \frac{275}{27}

Maximum (- \frac{1}{3}, \frac{275}{27})

Plug

x = 1

into

x^{3} - x^{2} - x + 10 : 9

Minimum (1, 9)

Maximum (- \frac{1}{3}, \frac{275}{27}), Minimum (1, 9)

f (x, y) = x^{3} + x y^{2} + 6 x y

f (x) = 5 cos (2 x) + 5

x^{2} y - 2 x y + 2 y^{2} x

f (x, y) = 4 x y - 2 x^{4} - y^{2} + 4 x - 2 y

f (x) = 5 (x - 3)^{2} (2 x + 1) (x + 4)^{3}

What is the extreme f(x)=x^3-x^2-x+10 ?
The extreme f(x)=x^3-x^2-x+10 is Maximum(-1/3 , 275/27),Minimum(1,9)