What is the extreme f(x)=5cos(2x)+5 ?

The extreme f(x)=5cos(2x)+5 is Maximum(pin,10),Minimum(pi/2+pin,0)

Popular >

extreme f(x)=5cos(2x)+5

extreme points

f (x) = 5 cos (2 x) + 5

Maximum (πn, 10), Minimum (\frac{π}{2} + πn, 0)

Solution steps

Find the critical points:

x = πn, x = \frac{π}{2} + πn

Domain of

5 cos (2 x) + 5 : - \infty < x < \infty

Find intervals:

Decreasing

: πn < x < \frac{π}{2} + πn,

Increasing

: \frac{π}{2} + πn < x < π + πn

Plug the extreme point

x = πn

into

5 cos (2 x) + 5 \Rightarrow y = 10

Maximum (πn, 10)

Plug the extreme point

x = \frac{π}{2} + πn

into

5 cos (2 x) + 5 \Rightarrow y = 0

Minimum (\frac{π}{2} + πn, 0)

Maximum (πn, 10), Minimum (\frac{π}{2} + πn, 0)

x^{2} y - 2 x y + 2 y^{2} x

f (x, y) = 4 x y - 2 x^{4} - y^{2} + 4 x - 2 y

f (x) = 5 (x - 3)^{2} (2 x + 1) (x + 4)^{3}

f (x) = 2 x - 1.75 x^{2} + 1. 1^{3} - 0.25 x^{4}

f (x y) = - x^{2} - y^{2} + 22 x + 18 y - 102

What is the extreme f(x)=5cos(2x)+5 ?
The extreme f(x)=5cos(2x)+5 is Maximum(pin,10),Minimum(pi/2+pin,0)