What is the extreme f(x)=x^3+3x^2-24x+6 ?

The extreme f(x)=x^3+3x^2-24x+6 is Maximum(-4,86),Minimum(2,-22)

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extreme f(x)=x^3+3x^2-24x+6

extreme points

f (x) = x^{3} + 3 x^{2} - 24 x + 6

Maximum (- 4, 86), Minimum (2, - 22)

Solution steps

f^{'} (x) = 3 x^{2} + 6 x - 24

Find intervals:

Increasing

: - \infty < x < - 4,

Decreasing

: - 4 < x < 2,

Increasing

: 2 < x < \infty

Plug

x = - 4

into

x^{3} + 3 x^{2} - 24 x + 6 : 86

Maximum (- 4, 86)

Plug

x = 2

into

x^{3} + 3 x^{2} - 24 x + 6 : - 22

Minimum (2, - 22)

Maximum (- 4, 86), Minimum (2, - 22)

y = x^{3} - 6 x^{2} + 9 x + 1

f (x) = \frac{x ^{2}}{x ^{2} + 48}

f (x, y) = ln (3 - 4 x^{2} - 5 y^{2})

y = x^{2} + 9 x - 2

f (x) = 5 cos^{2} (x), (0, π)

What is the extreme f(x)=x^3+3x^2-24x+6 ?
The extreme f(x)=x^3+3x^2-24x+6 is Maximum(-4,86),Minimum(2,-22)