What is the domain of f(x)=sqrt(16-x^2)+sqrt(x+2) ?

The domain of f(x)=sqrt(16-x^2)+sqrt(x+2) is -2<= x<= 4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

domain of f(x)=sqrt(16-x^2)+sqrt(x+2)

domain

f (x) = 16 - x^{2} + x + 2

- 2 \leq x \leq 4

Interval Notation

[- 2, 4]

Solution steps

Find non-negative values for radicals:

- 2 \leq x \leq 4

The function domain

- 2 \leq x \leq 4

y = (7 - 8 x)^{2}

y = x^{2} + 2 x - 1

f (x) = 49 x + 72

f (x) = \frac{x ^{2} - 11 x - 12}{x + 4}

What is the domain of f(x)=sqrt(16-x^2)+sqrt(x+2) ?
The domain of f(x)=sqrt(16-x^2)+sqrt(x+2) is -2<= x<= 4