What is the extreme f(x,y)=3x^2-y^2 ?

The extreme f(x,y)=3x^2-y^2 is Saddle(0,0)

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extreme f(x,y)=3x^2-y^2

extreme points

f (x, y) = 3 x^{2} - y^{2}

Saddle (0, 0)

Solution steps

Find the critical points:

(0, 0)

\frac{\partial ^{2} f}{\partial x ^{2}} = - 2

D (x, y) = - 12

Check the sign of at each critical point

Check critical point

(0, 0) :

Saddle

Saddle (0, 0)

x^{2} + 4

\frac{x ^{3} + 38 x + 128}{x}, 1 \leq x \leq 10

x^{2} + 9

\frac{1}{x + 6}

3 x e^{y} - x^{3} - e^{3 y}

What is the extreme f(x,y)=3x^2-y^2 ?
The extreme f(x,y)=3x^2-y^2 is Saddle(0,0)