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Popular >

extreme f(x)=x^4+x^3+x^2+1

Solution

extreme points

f (x) = x^{4} + x^{3} + x^{2} + 1

Solution

Minimum (0, 1)

Solution steps

f^{'} (x) = 4 x^{3} + 3 x^{2} + 2 x

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{4} + x^{3} + x^{2} + 1 : 1

Minimum (0, 1)

Graph

Popular Examples

extreme f(x)=3x-6cos(x)extreme points

f (x) = 3 x - 6 cos (x)

extreme f(x)=x^{4/5}-7 extreme points

f (x) = x^{\frac{4}{5}} - 7

extreme f(x)=x^{4/5}-2 extreme points

f (x) = x^{\frac{4}{5}} - 2

extreme f(x)=x^{4/5}-5 extreme points

f (x) = x^{\frac{4}{5}} - 5

extreme f(x)=x^{-1/2}(x-3)extreme points

f (x) = x^{- \frac{1}{2}} (x - 3)

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^4+x^3+x^2+1 ?
The extreme f(x)=x^4+x^3+x^2+1 is Minimum(0,1)