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Popular >

extreme f(x)=x^{4/5}-7

Solution

extreme points

f (x) = x^{\frac{4}{5}} - 7

Solution

Minimum (0, - 7)

Solution steps

f^{'} (x) = \frac{4}{5 x ^{\frac{1}{5}}}

Find intervals:

Decreasing

: - \infty < x < 0,

Increasing

: 0 < x < \infty

Plug

x = 0

into

x^{\frac{4}{5}} - 7 : - 7

Minimum (0, - 7)

Graph

Popular Examples

extreme f(x)=x^{4/5}-2 extreme points

f (x) = x^{\frac{4}{5}} - 2

extreme f(x)=x^{4/5}-5 extreme points

f (x) = x^{\frac{4}{5}} - 5

extreme f(x)=x^{-1/2}(x-3)extreme points

f (x) = x^{- \frac{1}{2}} (x - 3)

extreme f(x)= 1/4 x^2-1/2 x+13/4 extreme points

f (x) = \frac{1}{4} x^{2} - \frac{1}{2} x + \frac{13}{4}

extreme f(x)=6x^2-12[-4.1]extreme points

f (x) = 6 x^{2} - 12 [- 4.1]

Frequently Asked Questions (FAQ)

What is the extreme f(x)=x^{4/5}-7 ?
The extreme f(x)=x^{4/5}-7 is Minimum(0,-7)